为自己加油

(1)+39(2)-65(3)一35

(1)X=+39[X]_原=[X]_反=[X]_补=0000000000100111(2)X=一65[X]_原=1000000001000001．[X]_反=1l11111110111110[X]_补=111111110111111(3X=一35[X]_原=1000000000100011[X]_反=11111111011100[X]补一1111111111011101